2x^2-882=0

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Solution for 2x^2-882=0 equation:



2x^2-882=0
a = 2; b = 0; c = -882;
Δ = b2-4ac
Δ = 02-4·2·(-882)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*2}=\frac{-84}{4} =-21 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*2}=\frac{84}{4} =21 $

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